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tonyh發表於 2022-1-27 13:27 | 只看該作者

for 迴圈 (二)

假設有一串列其內容如下：
list=["忠","孝","仁","愛","信","義","和","平"]

試以for迴圈，橫向顯示串列中的所有元素。

  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
複製代碼
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9#
張效騫發表於 2022-1-27 13:52 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")

  5. list=["忠","孝","仁","愛","信","義","和","平"]
  6. for i in range(0,8):
  7.     print(list[i],end=" ")
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8#
富溢發表於 2022-1-27 13:46 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
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7#
林柏勳發表於 2022-1-27 13:45 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(8):
  3.     print(list[i],end=" ")
  4. for s in list
  5.     print(s,end=" ")
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6#
張仲言發表於 2022-1-27 13:44 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
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5#
黃裕恩發表於 2022-1-27 13:43 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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4#
胡孟涵發表於 2022-1-27 13:42 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
  4.    
  5. for s in list :
  6.     print(s,end=" ")
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Rank: 1
3#
林柏諺發表於 2022-1-27 13:41 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3. print(s,end=" ")
複製代碼

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Rank: 1
2#
張仲言發表於 2022-1-27 13:40 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
複製代碼

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