APCS 觀念題 10503 - 24、25 (易) 解析

葉桔良

24
g(4)

i                   j
-------------------
1   j=j+f(1)  6
2   j=j+f(2)  11
3   j=j+f(3)  13

f(1)
=1+f(2)
=1+3+f(3)
=1+3+1+f(4)
=1+3+1+1
=6

f(2) = 5
f(3) = 2

25
Mystery(9)
->Mystery(7){13} + Mystery(8){21}

Mystery(8)
->Mystery(6){8} + Mystery(7){13}

Mystery(7)
->Mystery(5){5} + Mystery(6){8}

Mystery(6)
->Mystery(4){3} + Mystery(5){5}

Mystery(5)
->Mystery(3){2} + Mystery(4){3}

Mystery(4)
->Mystery(2){1} + Mystery(3){2}

Mystery(3)
->Mystery(1){1} + Mystery(2){1}

Mystery(2)
->Mystery(0){0} + Mystery(1){1}