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標題: for 迴圈 (三) [打印本頁]

作者: 鄭繼威    時間: 2022-7-19 02:28     標題: for 迴圈 (三)

#range(start,stop,step)
#range(1,6)->[1,2,3,4,5]

試宣告兩個串列,一個存放班級名稱,一個存放人數,搭配 for 迴圈顯示五年級各班人數,執行畫面如下:

  1. list1=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=[28,27,27,26,28,29,30,27]
  3. for i in range(8):
  4.     print("五年{}班有{}人".format(list1[i],list2[i]))
複製代碼

作者: 鄭繼威    時間: 2022-7-19 15:08

  1. list1=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=[28,27,27,26,28,29,30,27]

  3. #range(0,8)->[0...7]
  4. for i in range(0,8):
  5.     print(f"五年{list1[i]}班有{list2[i]}人")
複製代碼

作者: 張晏齊    時間: 2022-7-19 15:13

  1. # -*- coding: utf-8 -*-
  2. """
  3. Spyder Editor

  4. This is a temporary script file.
  5. """
  6. list1=["忠","孝","仁","愛","信","義","和","平"]
  7. list2=[28,27,27,26,28,29,30,27]


  8. #range(0,8)->[0...7]
  9. for i in range(0,8):
  10.     print(f"五年{list1[i]}班有{list2[i]}人")
複製代碼

作者: 盧宥熏    時間: 2022-7-19 15:13

  1. list1=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=[28,27,27,26,28,29,30,27]
  3. for i in range (0,8):
  4.     print(f"五年{list1[i]}班有{list2[i]}人")
複製代碼

作者: 陳羨芮    時間: 2022-7-19 15:14

  1. list1=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=[28,27,27,26,28,29,30,27]
  3. for i in range(8):
  4.     print(f"五年{list1[i]}班有{list2[i]}人")
複製代碼

作者: 盧宥廷    時間: 2022-7-19 15:15

  1. list1=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=[28,27,27,26,28,29,30,27]
  3. for i in range(0,8):
  4.     print(f"五年{list1[i]}班有{list2[i]}人")
複製代碼

作者: 李宥廷    時間: 2022-7-19 15:15

  1. list1=b=["忠","孝","仁","愛","信","義","和","平"]
  2. list2=c=[28,27,27,26,28,29,30,27]
  3. for a in range(8):
  4.     print(f"五年{b[a]}有{c[a]}人")
複製代碼





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